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A substance undergoes first order decomp...

A substance undergoes first order decomposition. The decomposition follows two parallel first order reactios as:
and `K_(1)=1.26xx10^(-4)"sec"^(-1),K_(2)=3.80xx10^(-5)"sec"^(-1)`

The percentage distribution of B and C are

A

80% B and 20%C

B

76.83% B and 23.17%C

C

90%B and 10%C

D

60%B and 40%C

Text Solution

Verified by Experts

The correct Answer is:
B
`y_(B)=(K_(1))/(K_(1)+K_(2))=(1.26xx10^(-4))/((1.26+0.380)10^(-4))=1.26/1.64=0.76.88,y_(B)=76.88%y_(c)=23.2`
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