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In a zero order reactionn 47.5% of the r...

In a zero order reactionn 47.5% of the reactant remains at the end of 2.5 hours. The amount of reactant consumed in one hour is

A

0.105

B

0.32

C

0.526

D

0.21

Text Solution

Verified by Experts

The correct Answer is:
D
`C_(0)-C_(t)=K.t`……………(1), `x=Kxx1`….2 `52.5/x=2.5/1impliesx=52.5/2.5=21`
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