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By what fraction the Ea should be decrea...

By what fraction the Ea should be decreased in order to increase the rate by 10 times at 300 K (initial Ea=8.314kJ/mol) by use of a catalyst?

A

0.79

B

0.84

C

0.76

D

0.69

Text Solution

Verified by Experts

The correct Answer is:
D
`(r_(2))/(r_(1))=(K_(2))/(K_(1))=(a.e^(-epsilon a_(2)//RT_(2)))/(A.e^(Ea_(1)//RT_(1)))to` cat
`to` Not cat: ` (10r)/r=(A.e^(epsilona_(2)//RT))/(A.e^(-epsilona_(1)//RT)),2.303xxlog_(10)^(10)=In[e^(((-epsilona_(2)+epsilona_(1))/(RT)))]`
`2.303xx1=(-epsilon_(a_(2))+epsilon_(a_(1)))/(RT),(DeltaE_(a))/(epsilon_(a_(1)))=(2.303xx8.314xx300)/(8.314xx1000)=0.6909,(DeltaE_(a))/(epsilon_(a_(1)))=0.6909`
`25^(@)Cto35^(@)Cto45^(@)Cto55^(@)C`
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