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For a reactionAtoB with activation energ...

For a reaction`AtoB` with activation energy `E_(a)` and rate constant `k=Ae^(-Ea//RT)`. The rate of the reaction (Rate `=k[A]`) increases by increasing the temperature because

A

activation energy decreases with increase in temperature

B

The factor -Ea/RT increases

C

less number of collision take place

D

the value of [A] increases

Text Solution

Verified by Experts

The correct Answer is:
B
If temperature increases, then `((-Ea)/(RT))` increases
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