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Consider the following parallel reaction...

Consider the following parallel reaction being given `A(t_(1//2)=1.386xx10^(2)hrs)`, each path being first order.

If the distribution of B in the product mixture is 50%, the partial half life of A for conversion into C is

A

346.5 hr

B

131 hr

C

115.5 hr

D

31 hr

Text Solution

Verified by Experts

The correct Answer is:
A
`(t_(1/2))=((t_(1/2))xx(t_(1/2))_(2))/((t_(1/2))+(t_(1/2))_(2))=138.6`…….1 `, (t_(1/2))_(2)=1.5xx(t_(1/2))_(1)`……2 from 1 and 2 `(t_(1/2))_(2)=346.5`
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