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Boran forms a number of hydrides having ...

Boran forms a number of hydrides having the general formulae `BnH_(n+4)` and `BnH_(n+6)`. These are called boranes the simplest hydride of boran is diborane. Borane contains special types of bonds known as multicentric bonds. Borans have high heat of combustion.
Which hydrid doesnot exist.

A

`BH_(3)`

B

`H_(2)F_(2)`

C

`sbH_(3)`

D

`N_(2)H_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`BH_(3)` because of its structure.
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Boran forms a number of hydrides having the general formulae BnH_(n+4) and BnH_(n+6) . These are called boranes the simplest hydride of boran is diborane. Borane contains special types of bonds known as multicentric bonds. Borans have high heat of combustion. The type of hybridisation of boron in diborane is

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Structural isomers have different covalent linkage of atoms. Stereoisomers are compounds that have same sequence of covalent bonds but differ in the relative dispositions of their atoms in space. Geometri cal and optical isomers are the two important types of configurational isomers. The compound with double bonds or ring structure have restricted rotation, so exist in two geometrical forms. The double bonds in larger rings (ring size 10 carbon large) can also cause geometrical isomerism. The optical isomers rotate the plane of plane-polarised light. A sp^(3) -hybridised carbon atom bearing four different types of substituents is called an asymmetric centre or chiral centre. A chiral object or molecule cannot be superimposed on its mirror image. Stereoisomers that are mirror images of each other are called enantiomers. The stereosomers that the pot mirror images of each other are called diastereomers. Diasteremers have different physical properties. A racemic mixture is optically inactive and contains equal amounts of both the enantiomers. Resolution refers to method of separating a racemic mixture. Into two pure enantiomers. A meso compound is an optically inactive stereoisomer, which is achiral due to the presence of an internal plane of symmetry or centre of symmetry within the molecule. The number of chiral centres present in the following compounds is

Valence bond theory successfully explains the magnetic behaviour of complexes. The substances which contains unpaired electrons are paramagnetic and paramagnetic character increases as the number of unpaired electrons increases. Magnetic moment of a complex can be determined experimentally and by using formula sqrt(n(n+2)) and we can determine the number of unpaired electrons in it. This information is important in writing electronic structure of complex which in turn also useful in deciding the geometry of complex. The magnetic moment of complexes given below are in the order : {:(Ni(CO)_(4),[Mn(CN)_(6)]),("(I)","(II)"),([Cr(NH_(3))_(6)]^(3+),[CoF_(6)]^(3+)),("(I)","(II)"):}

Structural isomers have different covalent linkage of atoms. Stereoisomers are compounds that have same sequence of covalent bonds but differ in the relative dispositions of their atoms in space. Geometri cal and optical isomers are the two important types of configurational isomers. The compound with double bonds or ring structure have restricted rotation, so exist in two geometrical forms. The double bonds in larger rings (ring size 10 carbon large) can also cause geometrical isomerism. The optical isomers rotate the plane of plane-polarised light. A sp^(3) -hybridised carbon atom bearing four different types of substituents is called an asymmetric centre or chiral centre. A chiral object or molecule cannot be superimposed on its mirror image. Stereoisomers that are mirror images of each other are called enantiomers. The stereosomers that the pot mirror images of each other are called diastereomers. Diasteremers have different physical properties. A racemic mixture is optically inactive and contains equal amounts of both the enantiomers. Resolution refers to method of separating a racemic mixture. Into two pure enantiomers. A meso compound is an optically inactive stereoisomer, which is achiral due to the presence of an internal plane of symmetry or centre of symmetry within the molecule. The following two compounds are

AAKASH SERIES-ELEMENTS OF BORON FAMILY-PRACTICE SHEET (EXERCISE - I) LEVEL - II (ADVANCED)
  1. Ortho boric acid and metaboric acid differ in respect of

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  2. Possible oxidation states of boron family elements are

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  3. Which among the following is acts as reducing agent ?

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  4. Which of the following statement is correct ?

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  5. Which of the following is basic in nature ?

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  6. Which of the following has lowest melting point ?

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  7. Which halides of element of group 13 exist as dimer in vapour state ?

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  8. Which of the following does not exhibit inert pair effect ?

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  9. The heavier members of 13 and 14 groups besides the group oxidation st...

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  10. The heavier members of 13 and 14 groups besides the group oxidation st...

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  11. The heavier members of 13 and 14 groups besides the group oxidation st...

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  12. Boran forms a number of hydrides having the general formulae BnH(n+4) ...

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  13. Boran forms a number of hydrides having the general formulae BnH(n+4) ...

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  14. Boran forms a number of hydrides having the general formulae BnH(n+4) ...

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  15. Boran forms a number of hydrides having the general formulae BnH(n+4) ...

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  16. {:(,"Column - I",,"Column - II"),((A),"Graphite",(P),"Layered structur...

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  17. How many moles of NO(2) are produced when mole of 'B' react with HNO(3...

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  18. How much nitrogen is evolved when one gm of NH(4)Cl is heated with bor...

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  19. Number of hexagonal rings in borax.

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  20. The number of hydrogen bonds that can be formed by each borax acid mol...

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