Aldehydes and ketones react with `NH_2 OH` under slightly acidic condition, to give oximes. The oximes undergo rearrangement in acid medium togive amides. The migrating group does not lose its configuration as it is intramoleculon migration. The migrating group is always the one which is anti to the leaving group.
` CH_3 CHO +NH_2 OH overset(Delta) H^( +) to Q overset(Br_2 //KOH) to R (CH_3 NH_2)` (as only product) following is correct

Options

A. Oxime P is syn form of geometrical isomer
B. Oxime P is anti form
C. Q is more basic than R
D. `OHCNHCH_3`

Answer

A

Explanation

`CH_3 - overset(O) overset(||)C -H +NH_2 OH overset( Delta ) to P overset( H^(+)) to Q overset(Br_2 //KOH) to R (CH_3 NH_2)`

Transform ` CH_3 - NH - overset(O) overset(||)C - H overset(Br_2 KOH)to CH_3 -NH - overset(O) overset(||) -H`
cis form `NH_2 - overset(O ) overset(||)C -CH_3 overset(KOH //Br_2) to NH_2 -CH_3 implies C` is form gives ` CH_3 NH_3`
Transform doesn.t react with `KOH//Br_2` to give `CH_3 NH_2` Hence p must be cis form