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On treatment of [Ni(NH(3))(4)]^(+2) wit...

On treatment of `[Ni(NH_(3))_(4)]^(+2)` with conc.HC/ two compounds I and II having the same formula `[Ni(NH_(3))_(2)Cl_(2)]` are obtained, I can be converted into II by boiling with dil.HCI. A solution of I reacts with oxalic acid to form `[Ni(NH_(3))_(2)(C_(2)O_(4))]` where as II does not react. Point out the correct statement from the following

A

I cis, II trans, both tetrahedral

B

I cis, II trans both square planar

C

I trans, II cis, both tetrahedral

D

I trans, Il cis both square planar

Text Solution

Verified by Experts

Cis-form reacts with `C_(2)O_(4)^(2-)` trans-form does not react with `C_(2)O_(4)^(2-)`
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