Home
Class 12
CHEMISTRY
Amongst I=[Co(Ox)(3)]^(3-),II=[CoF(6)]^(...

Amongst `I=[Co(Ox)_(3)]^(3-),II=[CoF_(6)]^(3-),III=[Co(NH_(3))_(6)]^(+3)`

A

I, II are para, and III is dia

B

I, III are para, and II is dia

C

I, III are dia, and II in para

D

II, III are para, and I is dia

Text Solution

Verified by Experts

I. `[Co("ox")_(3)]^(3-)` : ox acts as SFL all paired electrons diamagnetic.
II) `[CoF_(7)]^(3-):` F acts as WFC 4, un in paired electron present, paramagnetic.
III. `[Co(NH_(3))_(6)]^(3+):NH_(3)` acts as SFL, all paired electron diamagnetic
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATION COMPOUNDS

    AAKASH SERIES|Exercise PRACTICE SHEET - 5 ( Linked Comprehension type questions Passage : 1 :)|3 Videos
  • CO-ORDINATION COMPOUNDS

    AAKASH SERIES|Exercise PRACTICE SHEET - 5 ( Linked Comprehension type questions Passage : I I:)|3 Videos
  • CO-ORDINATION COMPOUNDS

    AAKASH SERIES|Exercise PRACTICE SHEET - 4 (Integer answer type Questions )|6 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    AAKASH SERIES|Exercise PRACTICE SHEET - 2 (PRACTICE SHEET -2 (INTEGER ANSWER TYPE QUESTIONS))|7 Videos
  • COMPLEX COMPOUNDS

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos

Similar Questions

Explore conceptually related problems

All the following complex ions are found to be paramagnetic P=[FeF_(6)]^(3-) Q=[CoF_(6)]^(3-) R=[V(H_(2)O)_(6)]^(3+) S=[T:(H_(2)O)_(6)]^(3+) The correct order of their paramagnetic moment (spin only) is

CaCl_(3), xNH_(3) is a complex compound obtained by dissolving CoCl_(3) in ammonia . The complex compound is denoted at [Co(NH)36-x]Cl_(3)-x (soluble 100% insible The chlorides shown inside the square breackets are not ionisable . The salt ioniss as [Co(NH_(3))_(6-x)Cl_(x)]Cl_(3-x)rarr[Co(NH_(3))_(6-x)Cl_(x)]^(+(3-x))+(3-x)Cl 0.1M CoCl_(3).nNH_(3) solution has same osmatic pressure as 0.1M glucose solution . What is 'n'

CaCl_(3), xNH_(3) is a complex compound obtained by dissolving CoCl_(3) in ammonia . The complex compound is denoted at [Co(NH)36-x]Cl_(3)-x (soluble 100% insible The chlorides shown inside the square breackets are not ionisable . The salt ioniss as [Co(NH_(3))_(6-x)Cl_(x)]Cl_(3-x)rarr[Co(NH_(3))_(6-x)Cl_(x)]^(+(3-x))+(3-x)Cl 0.1M CoCl_(3).xNH_(3) solution is found to boil t 100.104^(@)C (Kb "of water "=0.52K Kg "mol"^(-1)) What x? 'alpha' of salt =1)

Valence bond theory successfully explains the magnetic behaviour of complexes. The substances which contains unpaired electrons are paramagnetic and paramagnetic character increases as the number of unpaired electrons increases. Magnetic moment of a complex can be determined experimentally and by using formula sqrt(n(n+2)) and we can determine the number of unpaired electrons in it. This information is important in writing electronic structure of complex which in turn also useful in deciding the geometry of complex. The magnetic moment of complexes given below are in the order : {:(Ni(CO)_(4),[Mn(CN)_(6)]),("(I)","(II)"),([Cr(NH_(3))_(6)]^(3+),[CoF_(6)]^(3+)),("(I)","(II)"):}

Identify the number of complexes that are optically active [Co("en")_(3)]^(3+), [Co(NH_(3))_(4)Cl_(2)]^(+) [CoCl_(2) ("en")_(2)] , [Co(NH_(3))_(3)(NO_(2))_(3)]

Draw all the isomers (geometrical and optical) of : (i) [CoCl_(2)(en)_(2)]^(+) (ii) [Co(NH_(3))Cl(en)_(2)]^(2+) (iii) [Co(NH_(3))_(2)Cl_(2)(en)]^(+)

Specify the oxidation numbers of the metals in the following coordination entities: (i) [Co(H_(2)O)(CN)(en)_(2)]^(2+) (ii) [CoBr_(2)(en)_(2)]^(+) (iii) [PtCl_(4)]^(2-) (iv) K_(3)[Fe(CN)_(6)] (v) [Cr(NH_(3))_(3)Cl_(3)]

{:("COLUMN-I","COLUMN-II"),((A)[Mn(H_(2)O)_(6)]^(2+),(p)"Paramagnetic"),((B)[Mn(CN)_(6)]^(3+),(q)"Diamagnetic"),((C)[Co(NH_(2))_(6)]^(3+),(r)"High spin complex (or) outer orbital complex"),((D)[Ni(NH_(3))_(6)]^(2+),(s)"Low spin complex (or) inner orbital complex"):}

Conjugate base of [Cu(NH_(3))_(6)]^(2+) is