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int log x dx=...

`int log x dx=`

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The correct Answer is:
x (log x - 1) + c
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Knowledge Check

  • int sin (log x)dx=

    A
    `(x)/(2)[sin (logx)-cos(logx)]+c`
    B
    `(x)/(2)[sin (logx)-cos(logx)]-x+c`
    C
    `(x)/(2)[sin (logx)+cos(logx)]+c`
    D
    `(x)/(2)[sin (logx)+tan(logx)]-c`

  • For x gt 0 , if int (log x)^5 dx =x[A (logx)^5+B(logx)^4+C(logx)^3+D(logx)^2+E(logx)+F]+ constant , then A+B+C+D+E+F= .

    A
    `-44`
    B
    `-42`
    C
    `-40`
    D
    `36`

  • int e^(x) (x+1) log x dx=

    A
    `e^(x)(x log x-1)-x+c`
    B
    `e^(x)(x log x-1)+c`
    C
    `e^(x)(x log x+1)+c`
    D
    none

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    int(log x)^2dx =

    int (log x )^(3) dx =

    int x^(x) ( 1 + log x ) dx =

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