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AAKASH SERIES-DEFINITE INTEGRALS-EXERCISE - II
- int(1//2)^(1) (1)/(sqrt(x-x^(2)))dx=
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- int(0)^(oo) (dx)/((x+sqrt(x^(2)+1))^(3))=
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- If int(0)^(b)(dx)/(1+x^(2))=int(b)^(oo)(dx)/(1+x(2)), then b=
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- int(0)^(pi//2) (8+7 cos x )/((7+8 cos x)^(2))dx is equal to
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- int(1//3)^(1) ((x-x^(3))^(1//3))/(x^(4))dx=
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- int(1)^(e) ((ln x )^(3))/(x) dx=
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- int(2)^(4) (sqrt(x^(2)-4))/(x^(4))dx=
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- int(0)^(1) sin (2 tan^(-1) sqrt((1+x)/(1-x)))dx =
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- int(0)^(pi//2) (Sinx+Cos x)/(3+ Sin 2x)dx=
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- int(0)^(pi//4) [sqrt(tan x)+sqrt(cot x)]dx
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- 2 int(0)^(1) (tan^(-1)x)/(x) dx=
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- If int(0)^(oo)(x^(2)dx)/((x^(2)+a^(2))(x^(2)+b^(2))(x^(2)+c^(2)))=(pi)...
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- int(0)^(pi) (1)/(3+2 sin x+ cos x)dx=
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- int(0)^(pi//2) sin 2x .tan^(-1)(sin x)dx=
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- int(0)^(1)(xSin^(-1)x)/(sqrt(1-x^(2)))dx=
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- int(0)^(pi//2) e^(x)((1+sin x)/(1+cos x))dx=
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- int(2)^(e) ((1)/(ln x) - (1)/((ln x)^(2)))dx=
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- If A = int(0)^(1) (e^(t))/(1+ t)dt then int(0)^(1) e^(t) ln (1 + t) dt...
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- int(0)^(1) ((1-x^(2))dx)/(x^(4)+x^(2)+1)=
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- If k int(0)^(1) x f (3 x) dx = int(0)^(3) t f(t) dt then k=
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