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AAKASH SERIES-DEFINITE INTEGRALS-EXERCISE - II
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- If f(a+b-x)=f(x)," then "int(a)^(b)xf(x)dx=
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- int(2)^(5) ([x^(2)+49-14x])/([x^(2)-14x+49]+[x^(2)])dx=
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- int(-1)^(1) (2 sinx - 3x^(2))/(4-|x|)dx=
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- int(-1)^(1) (17x^(5)-x^(4)+29 x^(3) -31 x +1)/(x^(2)+1)dx=
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- int(-pi)^(pi) (2x(1+Sin x))/(1+Cos^(2)x)dx=
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- If f(x)=[(x, cos x, e^(x^(2))),(sin x, x^(2), secx),(tan x, x^(4) ,2x^...
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- sum(n=1)^(10)int(-2n-1)^(2n)sin^(27) x dx + sum(n=1)^(10)int(2n)^(2n+1...
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- int(-3pi//2)^(-pi//2)[(x+pi)^(3)+cos^(2)(x+3pi)]dx=
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- int(-pi//2)^(pi//2)cos^(3)theta(1+sin theta)^(2)d theta=
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- int(- pi/4)^(pi/4) cos^(-4) x dx=
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- int(ln lambda)^(ln(1/lambda))(f(x^(2)/3)(f(x)+f(-x)))/(g(3x^(2))(g(x)-...
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- int(-1)^(1)(1)/((1+x^(2))^(2))dx=
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- f(x)= int(0)^(x) ln ((1-t)/(1+t))dt rArr
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- int(0)^(a) (f(x)+f(-x))dx=
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- int(-1)^(3)(Tan^(-1)""(x)/((x^(2)+1))+Tan^(-1)""(x^(2)+1)/(x))dx=
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- int(0)^(sin^(2)x) sin^(-1) sqrt(t) dt + int(0)^(cos^(2)x) cos^(-1) sqr...
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- int(0)^(1) cot^(-1) (1-x+x^(2))dx=
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