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Using integration, find the area of the ...

Using integration, find the area of the region bounded by the triangle whose vertices are `(-1, 2), (1, 5) and (3, 4)`.

Text Solution

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Equations of AB,BC and AC are
`y = 1/2 (3x +7 ), y= 1/2 (11-x)`
and `y =1/2(3x + 7 ),y =1/2(11-x)`
and `y = 1/2 (x+5)` respectively
`therefore Delta =1/2underset(-1)overset(1)int (3x+7)dx + 1/2underset(1)overset(3)int (11-x)dx -1/2underset(1)overset(3)int (x+5)dx`
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RS AGGARWAL-AREA OF BOUNDED REGIONS -Exercise 17
  1. Using integration, find the area of the region bounded by the lines Y ...

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  2. Find the area bounded by the curve y=(4-x^2) the y-axis and the lines ...

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  3. Using integration, find the area of the region bounded by the triangle...

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  4. Using integration, find the area of the region bounded by the lines...

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  5. Using intergration find the are of the region bounded between the lin...

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  6. Using integration, find the area of the region bounded by the line y-1...

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  7. Sketch the region lying in the first quadrant and bounded by y = 4x^2 ...

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  8. Sketch the region lying in the first quadrant and bounded by y=9x^2...

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  9. Find the area of the region enclosed between the two circles x^2 + y^2...

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  10. Sketch the region common to the circle x^2 +y^2=16 and the parabola x...

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  11. Sketch the region common to the cirvle x^2+y^2=25 and the parabola y^...

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  12. Draw a rough sketch of the region {(x,y): y^2 le 3x,3x^2 + 3y^2 le16 }...

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  13. Draw a rough sketch and find the area of the region bounded by the par...

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  14. Find by intergraiton the area bounded by the curve y^2 = 4ax and the l...

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  15. Draw a rough sketch of the curve y=x/pi + 2 sin^2 x, and find the area...

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  16. Find the area bounded by the curve y=cos x between x=0 and x=2pi

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  17. Compare the areas under the curves y=cos ^2 x and y= sin ^2x between x...

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  18. Using integration find the area of the triangular region whose side...

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  19. Find the area of the region {(x,y) : x^2 le y le x }

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  20. Examples: Find the area of the region bounded by the curve y^2 = 2y - ...

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