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The displacement of two particles execut...

The displacement of two particles executing SHM are represented by equations, `y_(1)=2 sin (10 t + theta), y_(2)=3 cos 10 t`. The phase difference between the velocity of these particles is

A

`theta`

B

`-theta`

C

`theta+(pi)/(2)`

D

`theta-(pi)/(2)`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

    A
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    B
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  • The equation of the displacement of two particles making SHM are represented by y_(1) = a sin (omegat +phi) & y_(2) - a cos (omegat) . Phase difference between velocities of two particles is

    A
    `(pi)/(2) +phi`
    B
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  • The displacement of two identical particles executing SHM are represented by equations. x_(1) = 4sin(10t+pi/6) and x_(2)=5cosepsilont For what value of epsilon of both the particles is same?

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