The total electric flux through a cube when a charge 8q is placed at one corner of the cube is

Options

A. `(2q)/(epsilon_(0))`
B. `(q)/(8epsilon_(0))`
C. `(q)/(epsilon_(0))`
D. `(q)/(2epsilon_(0))6a^(2)`

Answer

B

Explanation

Eight identical cubes are required so that the given charge q appears at the centre of the bigger cube.
Thus, the electric flux passing through the given cube is
`phi = (1)/(8)((q)/(epsilon_(0))) = (q)/(epsilon_(0))`