A silver wire has a resistance of `2.1 Omega` at `27.5^@C`, and a resistance of `2.7 Omega` at `100^@C`, Determine the temperature coefficient of resistivity of silver.

Explanation

Resistance of a conductor changes with the temperature, if `alpha` is taken as temperature coefficient of resistivity then the relation is
`R_(2)=R_(1)[1+alpha(t_(2)-t_(1))]`
`2.7=2.1[1+alpha(100-27.5)]`
`0.6=2.1alpha[72.5]`
`alpha=0.00394""^(@)C^(-1)`
`alpha=39.4xx10^(-4)""^(@)C^(-1)`