If the electric current through an electric bulb is 3.2 A, the number of electrons flow through it in 1 second is

Options

A. `2xx10^(9)`
B. `2xx10^(19)`
C. `3.2xx10^(9)`
D. `1.6xx10^(18)`

Explanation

To find the number of electrons flowing through an electric bulb in 1 second when the current is 3.2 A, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between current, charge, and time**:
The current (I) is defined as the rate of flow of charge (Q) per unit time (t). This can be expressed with the formula:
\[ I = \frac{Q}{t} \]
Rearranging gives us:
\[ Q = I \times t \]

2. **Substitute the known values**:
We know the current \(I = 3.2 \, \text{A}\) and the time \(t = 1 \, \text{s}\). Substituting these values into the equation gives:
\[ Q = 3.2 \, \text{A} \times 1 \, \text{s} = 3.2 \, \text{C} \]

3. **Relate charge to the number of electrons**:
The total charge (Q) can also be expressed in terms of the number of electrons (n) and the charge of a single electron (e). The charge of a single electron is approximately:
\[ e = 1.6 \times 10^{-19} \, \text{C} \]
The relationship is given by:
\[ Q = n \times e \]

4. **Set the two expressions for charge equal**:
From the previous steps, we have:
\[ 3.2 \, \text{C} = n \times (1.6 \times 10^{-19} \, \text{C}) \]

5. **Solve for the number of electrons (n)**:
Rearranging the equation to solve for n gives:
\[ n = \frac{3.2 \, \text{C}}{1.6 \times 10^{-19} \, \text{C}} \]
Now, calculating this:
\[ n = \frac{3.2}{1.6 \times 10^{-19}} = 2 \times 10^{19} \]

6. **Final result**:
Therefore, the number of electrons flowing through the bulb in 1 second is:
\[ n = 2 \times 10^{19} \]