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Two wires that are made up of two different materials whose specific resistance are in the ratio 2 : 3, length 3 : 4 and area 4 : 5. The ratio of their resistances is

A

`6:5`

B

`6:8`

C

`5:8`

D

`1:2`

Text Solution

Verified by Experts

The correct Answer is:
C

Resistance, `R=rho(l)/(A)`
`therefore (R_(1))/(R_(2))=(rho_(1))/(rho_(2))xx(l_(1))/(l_(2))xx(A_(2))/(A_(1))=(2)/(3)xx(3)/(4)xx(5)/(4)=(5)/(8)`
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