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Two resistances R(1)andR(2) provides ser...

Two resistances `R_(1)andR_(2)` provides series to parallel equivalents as n/1, then the correct relationship is

A

`((R_(1))/(R_(2)))^(3//2)+((R_(2))/(R_(1)))^(3//2)=n^(3//2)`

B

`((R_(1))/(R_(2)))^(3)+((R_(2))/(R_(1)))^(3)=n^(3)`

C

`((R_(1))/(R_(2)))^(2)+((R_(2))/(R_(1)))^(2)=n^(2)`

D

`((R_(1))/(R_(2)))^(1//2)+((R_(2))/(R_(1)))^(1//2)=n^(1//2)`

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The correct Answer is:
To solve the problem, we need to derive the relationship between the resistances \( R_1 \) and \( R_2 \) given that the ratio of their series equivalent to their parallel equivalent is \( \frac{n}{1} \). ### Step-by-Step Solution: 1. **Understand the Definitions**: - The series equivalent resistance \( R_s \) of two resistances \( R_1 \) and \( R_2 \) is given by: \[ R_s = R_1 + R_2 \] - The parallel equivalent resistance \( R_p \) is given by: \[ \frac{1}{R_p} = \frac{1}{R_1} + \frac{1}{R_2} \implies R_p = \frac{R_1 R_2}{R_1 + R_2} \] 2. **Set Up the Ratio**: - According to the problem, the ratio of the series equivalent to the parallel equivalent is: \[ \frac{R_s}{R_p} = \frac{n}{1} \] - Substituting the expressions for \( R_s \) and \( R_p \): \[ \frac{R_1 + R_2}{\frac{R_1 R_2}{R_1 + R_2}} = n \] 3. **Simplify the Equation**: - To simplify the left-hand side, we multiply both sides by \( R_p \): \[ (R_1 + R_2)^2 = n \cdot R_1 R_2 \] 4. **Rearranging the Equation**: - Rearranging gives us: \[ (R_1 + R_2)^2 = n R_1 R_2 \] 5. **Taking the Square Root**: - Taking the square root of both sides: \[ R_1 + R_2 = \sqrt{n} \sqrt{R_1 R_2} \] 6. **Dividing by the Square Roots**: - Dividing both sides by \( \sqrt{R_1 R_2} \): \[ \frac{R_1 + R_2}{\sqrt{R_1 R_2}} = \sqrt{n} \] 7. **Expressing the Left Side**: - The left side can be expressed as: \[ \frac{R_1}{\sqrt{R_2}} + \frac{R_2}{\sqrt{R_1}} = \sqrt{n} \] 8. **Final Relationship**: - Therefore, we conclude that: \[ \left( \frac{R_1}{R_2} \right)^{1/2} + \left( \frac{R_2}{R_1} \right)^{1/2} = \sqrt{n} \] ### Conclusion: The correct relationship derived from the given conditions is: \[ \left( \frac{R_1}{R_2} \right)^{1/2} + \left( \frac{R_2}{R_1} \right)^{1/2} = \sqrt{n} \]

To solve the problem, we need to derive the relationship between the resistances \( R_1 \) and \( R_2 \) given that the ratio of their series equivalent to their parallel equivalent is \( \frac{n}{1} \). ### Step-by-Step Solution: 1. **Understand the Definitions**: - The series equivalent resistance \( R_s \) of two resistances \( R_1 \) and \( R_2 \) is given by: \[ R_s = R_1 + R_2 ...
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