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The number of dry cells, each of e.m.f. ...

The number of dry cells, each of e.m.f. `1.5` volt and internal resistance `0.5 omega` that must be joined in series with a resistance of `20` ohm so as to send a current of `0.6` ampere through the circuit is -

A

2

B

8

C

10

D

12

Text Solution

Verified by Experts

The correct Answer is:
C
`0.6=(nxx1.5)/(nxx0.5+20)`
Solving, we get `n=10`
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MTG GUIDE-CURRENT ELECTRICITY -NEET CAFE ( TOPICWISE PRACTICE QUESTIONS )
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