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Two resistors whose value are in ratio 2...

Two resistors whose value are in ratio `2 : 1` are connected in parallel with one cell. Then ratio of power dissipated is

A

`2:1`

B

`4:1`

C

`1:2`

D

`1:1`

Text Solution

Verified by Experts

The correct Answer is:
C
`P=(V^(2))/(R)orPprop(1)/(R),so(P_(1))/(P_(2))=(R_(2))/(R_(1))=(1)/(2)`
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