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Time taken by a 836 W heater to heat one...

Time taken by a 836 W heater to heat one litre of water from `10^@C to 40^@C` is

A

`50 s`

B

`100 s`

C

`150 s`

D

`200 s`

Text Solution

Verified by Experts

The correct Answer is:
C
Mass of water, m = volume `xx` density = `1000xx1=1000g`
Heat taken by water = heat produced by heater
`therefore ms(theta_(2)-theta_(1))=(Pt)/(J)ort=(ms(theta_(2)-theta_(1))J)/(P)`
`t=(1000xx1xx(40-10)xx4.18)/(836)=150s`
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