`2A` cell having an emf `epsilon` and internal resistance `r` is connected across a variable external resistance `R`. As the resistance `R` is increased, the plot of potential difference `V` across `R` is given by

Options

A.
B.
C.
D.

Answer

C

Explanation

Current in the circuit,
`I=(epsilon)/(R+r)`
Potential difference across R,
`V=IR=((epsilon)/(R+r))R=(epsilon)/(1+(r)/(R))`
When `R=0, V=0`
`R=oo, V=epsilon`