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A series resonant LCR circuit has a qual...

A series resonant LCR circuit has a quality factor (Q-factor)=0.4. If `R=2k Omega, C=0.1 mu F` then the value of inductance is

A

0.1H

B

0.064 H

C

2H

D

5H

Text Solution

Verified by Experts

The correct Answer is:
B
`Q = 1/R sqrt(L/C) `
`L/C = (QR)^2`
`therefore L = (0.4 xx 2 xx 10^3)^2 xx 0.1 xx 10^(-6) = 0.0064 H`
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