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If E(0) is the peak emf , l(0) is the pe...

If `E_(0)` is the peak emf , `l_(0)` is the peak current and `phi` is the phase difference between them, then the average power dissipation in the circuit is

A

`1/2 E_0 I_0`

B

`(E_0 I_0)/(sqrt2)`

C

`1/2 E_0 I_0 sin phi`

D

`1/2 E_0 I_0 cos phi`

Text Solution

Verified by Experts

The correct Answer is:
D
Average power dissipation = `1/2 E_0 I_0 cos phi`
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