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A reactor is developing energy at the ra...

A reactor is developing energy at the rate of 3000 kW. How many atoms of `U^(235)` undergo fission per second, if 200 MeV energy is released per fission?

A

`6.5xx10^(22)`

B

`5.15xx10^(21)`

C

`3.384xx10^(23)`

D

`9.4xx10^(16)`

Text Solution

Verified by Experts

The correct Answer is:
D
Rate of development of energy by the reactor
`=3000 kW=3xx10^(6)Js^(-1)`
Energy released per fission = 200 MeV
`=200xx1.6xx10^(-13)J=32xx10^(-12)J`
Number of atoms undergoing fission per second
`=(3xx10^(6))/(32xx10^(-12))=9.4xx10^(16)`
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