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Calculate the energy released by the fis...

Calculate the energy released by the fission `1 g` of `.^(235)U` in joule, given that the energy released per fission is `200 MeV`.
(Avogadro's number `=6.023xx10^(23))`

A

`5.1xx10^(26)eV`

B

`5.1xx10^(26)J`

C

`8.2xx10^(13)J`

D

`8.2xx10^(13)` MeV

Text Solution

Verified by Experts

The correct Answer is:
C
Energy of single fission is 200 MeV.
Number of atoms is 235 g `=6.023xx10^(23)`
`therefore" Number of atoms in 1 kg of uranium 235"`
`=(1000)/(235)xx6.023xx10^(23)`
`therefore" Energy released in fission of 1 kg of "U^(235)`
`=(200xx10^(6)xx1000xx6.023xx10^(23)xx1.6xx10^(-19))/(235)J`
`=8.2xx10^(13)J`
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