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In solid PCl(5) exist as [PCl(4)]^(+) [P...

In solid `PCl_(5)` exist as `[PCl_(4)]^(+) [PCl_(6)]^(-)`. The hybridisation is P is /are

A

`sp^(3)`

B

`sp^(3)d`

C

`sp^(3)d^(2)`

D

`sp^(3) d^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A, C
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