In a solid AB, A atoms have a ccp arrangement and B atoms occupy all the octahedral sites. If all the face-centred atoms along one of the axes passing through body centres are removed, then what will be the resultant stoichiometry of compound ?

Explanation

Number of A atoms constituting ccp=4 (1 from 8 corners and 3 from 6 face centres )
On removing two face centes along one of the axis
Number of A atoms left in unit cell = 3
Number of B atoms occupying all octahedral voids =4
(3 from 12 edges centes and 1 froms body centre )
Hence, formula of compound is `A_3B_4` and stoichiometry is = 3:4