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KF and NaCl struture. If the distance be...

KF and NaCl struture. If the distance between ` K ^(+) and F^(-)` is 269 pm, find the denisty of KF ( ` N_(A) = 6.02 xx 10^(23) "mol"^(-1)` a atomic mass of copper = 63.5

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For NaCl type structure of KF
`a=2(r_(K^+)……. + r_(F^-))` or 2 x 269 =538 pm
`rho=(ZxxM)/(N_0xxa^3)=(4xx58)/(6.02xx10^23 xx(538xx10^(-10))^3`
`rho=2.48 "g/cm"^3`
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