Formula mass of `NaCl` is `58.45g mol^(-1)` and density of its pure form is `2.167g cm^(-3)`. The average distance between adjacent sodium and chloride ions in the crystal is `2.814xx10^(-8)cm`. Calculate Avogadro constant.

Explanation

Given M=58.5 `rho=2.167 "g/cm"^(-3)`
a=`2xx2.814xx10^(-8)`cm =`5.628xx10^(-8)` cm
`N_0`= ? , Z=4
`therefore N_0=(ZxxM)/(rhoxxa^3)=(4xx58.5)/(2.167(5.628xx10^(-10))^3`
`N_0=6.02xx10^23` atoms