Home
Class 12
CHEMISTRY
For a unit cell of edge length 10 Å, ato...

For a unit cell of edge length 10 Å, atomic mass of that element is 150 g and density is `1 g cm^(-3)`.Find out the atomic radius .

Text Solution

Verified by Experts

3.51 Å
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-J (AAKASH CHALLENGERS )|10 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise EXERCISE|30 Videos

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-H (MULTIPLE TRUE-FALSE)|3 Videos

  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE|Exercise Assignment (Section-J)|10 Videos

  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

A metal crystallises in FCC lattice. If edge length of the cell is 4xx10^(-8) cm and density is 10.5 g cm^(-3) then the atomic mass of metal is

For a unit cell edge length = 5 Å , the element is of atomic mass 75, has denstiy of 2gm/cc. Calculate atomic radius of the element

An element E crystallizes in body centred cubic structure. If the edge length of the cell is 1.469 xx 10^(-10)m and the density is 19.3 g cm^(-3) , calculate the atomic mass of this element. Also calculate the radius of an atom of the element.

An element occurs in bcc structure. It has a cell edge length of 250pm. Calculate the molar mass if its density is 8.0g cm^(-3) . Also calculate the radius of an atom of this element.

A element cystallizes in fcc lattice and edge length of unit cell is 400 pm. If density of unit cell is 11.2 g cm^(-3) , then atomic mass of the element is

The unit cell of an element having atomic mass 100 and density 12 g cm^(-3) is a cube with edge length 300 pm, the structure of crystal lattice is

The unit cell of a metallic element of atomic mass ( 108 g //"mole" ) and density 10.5 g//cm^(3) is a cube with edge length of 409 pm. The structure of the crystal lattice would be: