Home
Class 12
CHEMISTRY
KCI crystallizes in the same type of lac...

`KCI` crystallizes in the same type of lacttice as does `NaCl`. Given that
`(r_(Na^(o+)))/(r_(Cl^(Θ))) = 0.5` and `(r_(Na^(o+)))/(r_(K^(o+))) = 0.7`
Calculate (a) the ratio of side of the unit cell for `KCl` to that for `NaCl`, and (b) the ratio of density of `NaCl` to that `KCl`.

Text Solution

Verified by Experts

(a)1.143 , (b) 1.172
Promotional Banner

Topper's Solved these Questions

  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise EXERCISE|30 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise Assignment (SECTION - A) (OBJECTIVE TYPE QUESTION)|58 Videos
  • THE SOLID STATE

    AAKASH INSTITUTE|Exercise ASSIGNMENT SECTION-I (SUBJECTIVE)|10 Videos
  • THE S-BLOCK ELEMENTS

    AAKASH INSTITUTE|Exercise Assignment (Section-J)|10 Videos
  • THERMODYNAMICS

    AAKASH INSTITUTE|Exercise ASSIGNMENT (Section -D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

KCI cyrstallizes in the saem type of lattice as does NaCl. Given that (r_(Na^(o+))/(r_(Cl_(-)))=0.5 and (r_(Na^(o+)))/(r_(K^(o+)))=0.7 Calculate the ratio of side of the unit cell for KCl to that for NaCl.

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.