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Nitrogen forms largest number of oxides ...

Nitrogen forms largest number of oxides in which oxidation state of nitrogen varies from +1 to +5 `N_(2)O,NO,N_(2)O_(3),N_(2)O_(4) and N_(2)O_(5)` respectively. The largest number of oxides are formed due to capability of forming stable multiple bonds by nitrogen with oxygen.
Q. Which of the following is/are correct statement(s)?

A

In `N_(2)O_(4)` the N-N bond length is longer than the usual N-N single bond distance

B

`NO_(2)` molecule is angular and N-O bond length is intermediate between a single and a double bond

C

`N_(2)O` is linear molecule and has small dipole moment

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
D
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Nitrogen forms largest number of oxides in which oxidation state of nitrogen varies from +1 to +5 N_(2)O,NO,N_(2)O_(3),N_(2)O_(4) and N_(2)O_(5) respectively. The largest number of oxides are formed due to capability of forming stable multiple bonds by nitrogen with oxygen. Q. Which of the following statements is/are correct regarding oxides of nitrogen?

Nitrogen forms largest number of oxides in which oxidation state of nitrogen varies from +1 to +5 N_(2)O,NO,N_(2)O_(3),N_(2)O_(4) and N_(2)O_(5) respectively. The largest number of oxides are formed due to capability of forming stable multiple bonds by nitrogen with oxygen. Q. Which of the following oxides is known as anhydride of nitric acid?

N_(2)O_(3),N_(2)O_(4) and N_(2)O_(5) are anhydride of which axyacids.

The correct order of the oxidation states of nitrogen in NO, N_(2)O, NO_(2) and N_(2)O_(3) is :

Find the sum of oxidation number of nitrogen in (NH_(4))_(2)SO_(4), N_(2)H_(4) and N_(2)O_(4) .

Arrange in the increasing order of oxidation state of nitrogen for following nitrogen oxides N_(2)O, NO_(2), NO, N_(2)O_(3)