If two heaters, each of power 1 kW are connected in parallel to a 250 V supply, their combined rate of heating will be

Options

A. 1 kW
B. 2 kW
C. 5 kW
D. 250 W

Explanation

To solve the problem of finding the combined rate of heating of two heaters, each with a power of 1 kW connected in parallel to a 250 V supply, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Power Ratings**:
Each heater has a power rating of 1 kW. This means that when each heater is connected to the supply, it will consume 1 kW of power.

2. **Identify the Connection Type**:
The heaters are connected in parallel. In a parallel connection, the total power consumed is the sum of the individual powers of the devices connected.

3. **Apply the Formula for Parallel Connection**:
The formula for total power (P_net) in a parallel circuit is:
\[ P_{net} = P_1 + P_2 \]
where \(P_1\) and \(P_2\) are the power ratings of the individual heaters.

4. **Substitute the Values**:
Here, both heaters have the same power rating:
\[ P_1 = 1 \text{ kW}, \quad P_2 = 1 \text{ kW} \]
Therefore, substituting the values into the formula gives:
\[ P_{net} = 1 \text{ kW} + 1 \text{ kW} = 2 \text{ kW} \]

5. **Conclusion**:
The combined rate of heating of the two heaters connected in parallel is 2 kW.

### Final Answer:
The combined rate of heating will be **2 kW**.

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