100 ml, 0.1M `H_2SO_4` is exactly neutralized by 100 ml of NaOH solution. Calculate the molarity of NaOH solution.

Explanation

`H_2SO_4 +2NaOH to Na_2SO_4 + 2H_2O`
`(M_1V_1)/underset((H_2SO_4))(n_1)=(M_2V_2)/underset"(NaOH)"(n_2) , (0.1xx100)/1 = (M_2xx100)/2`
`M_2`=0.2 M, Therefore , molarity of NaOH is 0.2 M