200 ml of `KMnO_4` solution is exactly reduced by 100 ml, 0.5M oxalic acid solution. Find the molarity of `KMnO_4` solution.

Explanation

`2KMnO_4 + 3H_2SO_4 + 5H_2C_2O_4 to K_2SO_4 + 2MnSO_4 + 8H_2O + 10CO_2`
`(M_1V_1)/underset((KmnO_4))(n_1)=(M_2V_2)/underset((H_2C_2O_4))(n_2)`
`therefore (M_1xx200)/2=(0.5xx100)/5 , M_1`=0.1 M
`therefore` Molarity of `KMnO_4`=0.1 M