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What is molal elevation constant ?...

What is molal elevation constant ?

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What is molal depression constant ?

A dilute solutions "x" moles of A in 1kg of solvent with molal elevation constant K_(b) . The solution dimerises in the solution . 2AhArr A_(2) (alpha be degree of association) The molecular weight observed will be :

When some amount of non-volatile solute is dissolved in a solvent to prepare a dilute solution, the vapour pressure of the solvent is lowered and it is directly proportional to the mole fraction of solvent in the solution . Relative lowering in vapour pressure is equal to mole fraction of solute . Elevation in boiling point of solvent is a collgative property like lowering in vaour pressure of solvent in solution , K_(b) i.e., molal elevation constant is calculated by the formula, K_(b)=DeltaT_(b)// molality and also by the expression, K_(b)=RT_(b)^(2)//1000l_(v) where T_(b) is boiling point of solvent and I_(v) is latent heat of vapourisation for 1 gm solvent . Abnormal elevation is boiling point =iX elevation in boiling point in ideal solution where i=van't Hoff factor Molal elevation (K_(b))

When some amount of non-volatile solute is dissolved in a solvent to prepare a dilute solution, the vapour pressure of the solvent is lowered and it is directly proportional to the mole fraction of solvent in the solution . Relative lowering in vapour pressure is equal to mole fraction of solute . Elevation in boiling point of solvent is a collgative property like lowering in vaour pressure of solvent in solution , K_(b) i.e., molal elevation constant is calculated by the formula, K_(b)=DeltaT_(b)// molality and also by the expression, K_(b)=RT_(b)^(2)//1000l_(v) where T_(b) is boiling point of solvent and I_(v) is latent heat of vapourisation for 1 gm solvent . Abnormal elevation is boiling point =iX elevation in boiling point in ideal solution where i=van't Hoff factor Lowering in vapour pressure in an experiment was found to be x mm of Hg. It is : Lowering in vapour pressure in an experiment was found to be x mm of Hg. It is

The molal elevation constant is the ratio of the elevation in boliing point to

The molal elevation constant of water is 0.51. The boiling point of 0.1 molal aqueous NaCl solution is nearly:

When some amount of non-volatile solute is dissolved in a solvent to prepare a dilute solution, the vapour pressure of the solvent is lowered and it is directly proportional to the mole fraction of solvent in the solution . Relative lowering in vapour pressure is equal to mole fraction of solute . Elevation in boiling point of solvent is a collgative property like lowering in vaour pressure of solvent in solution , K_(b) i.e., molal elevation constant is calculated by the formula, K_(b)=DeltaT_(b)// molality and also by the expression, K_(b)=RT_(b)^(2)//1000l_(v) where T_(b) is boiling point of solvent and I_(v) is latent heat of vapourisation for 1 gm solvent . Abnormal elevation is boiling point =iX elevation in boiling point in ideal solution where i=van't Hoff factor Relative lowering in vapour pressure :

If molality of the dilute solution is doubled, the value of molal depression constant (K_f) will be

{:("COLUMN-I","COLUMN-II"),((A)"molar elevation constant",(p)(RT_(b)^(2))/(1000L_(v))),((B)"molecular elevation constant",(q)iK_(b)m),((C)"molal elevation constant",(r)(RT_(b)^(2)M)/(1000DeltaH_("rap"))),((D)"Elevation in B.P",(s)(RT_(b)^(0))/(100L_(v))):}