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On combustion of 0.2475 g of an organic ...

On combustion of 0.2475 g of an organic compound 0.4950 g of `CO_(2)` and 0.2025 g of `H_(2)O` were obtained. Find out the percentage of hydrogen.

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The correct Answer is:
9
`%"Hydrogen"=(2 xx "weight of" H_(2)O xx 100)/(18 xx "weight of organic compound")`
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