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If N(0) is the initial number of nuclie ...

If `N_(0)` is the initial number of nuclie , number of nuclei remaining undecayed at the end of nth half life is :

A

`2^(-n) N_(0)`

B

`2^(n) N_(0)`

C

`n^(-2) N_(0)`

D

`n^(2) N_(0)`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(t) = (N_(0))/(2^(n))`
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