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What is the quantity of charge needed fo...

What is the quantity of charge needed for the reduction of 1 mole of `MnO_4^(-)` ion to `Mn^(2+)` ion ?

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The correct Answer is:
5
`MnO_4^(-) to Mn^(+2) ,MnO_4^(-) + 5e^(-) to Mn^(+2) :. " charge " = 5 " faradays "`
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