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The resistance of 0.1 N solution of form...

The resistance of 0.1 N solution of formic acid is 200 ohm and cell constant is `2.0cm^(-2)`. The equivalent conductivity (in `Scm^(2)eg^(-1)`) of 0.1 N formic acid is `1.0 xx 10^(x)` , x is

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The correct Answer is:
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`R = S . (1)/(A) implies K =(1)/(S) = (2)/(200) = 10^(-2) , ^^_(e) = K xx (1000)/(N) = 10^(-2) xx (1000)/(10^(-1)) = 10^(2)`
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