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The resistance of a conductivity cell co...

The resistance of a conductivity cell containing 0.001M KCl solution at 298K is `1500Omega` .What is the cell constant (in`mm^(-1)`). If the conductivity of 0.001 M KCl solution is `2 xx 10^(-3) S mm^(-1)`

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The correct Answer is:
3
`R = S .(1)/(a) , 1500 = S. (1)/(a)`
cell constant = `(1)/(a) = (1)/(5) xx 1500 = 2 xx 10^(-3) xx 1500 = 300 xx 10^(-3) =3 `
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