Home
Class 12
CHEMISTRY
Molar conductivities at infinite diluti...

Molar conductivities at infinite dilution of KCl, HCl and `CH_3COOK` are 0.013o and 0.038 and `0.09 S m^(2) mol^(-1)` respectively at 291 K . If conductivity of 0.001 M `CH_3COOH` is ` 2.72 xx 10^(-3) Sm^(-1)` then find % degree of ionization of `CH_3COOH`.

Text Solution

Verified by Experts

The correct Answer is:
8
`^^_(M)^(0)[{:(^^_M^(0)+ , ^^_M^(0)- , ^^_M^(0)),(CH_3COOK, HCl , KCl):}]=(0.009 + 0.038 - 0.013)`
`^^_M^(0)(CH_3COH)=0.034 xx 10^(4) = 340S -cm^(2) -"mole"^(-1)`
`^^_M^(0) = (K xx 10^(3))/(M)=(2.72 xx 10^(-3)xx 10^(-2))/(0.001) = 2.72 xx 10`
`^^_M = 2.72 xx 10^(32) = 27.2 , alpha = (^^_M)/(^^_M^(0))=(27.2)/(340)=0.08, alpha % = 8%`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET -3 (SINGLE OF MORE THAN ONE OPTION QUESTIONS )|16 Videos

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET -3 (LINKED COMPREHENSION TYPE QUESTIONS(PASSAGE-I))|3 Videos

  • ELECTROCHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET -2 ( LINKED COMPREHENSION TYPE QUESTIONS (PASSAGE-II))|3 Videos

  • DILUTE SOLUTIONS

    AAKASH SERIES|Exercise EXERCISE - 1.2|55 Videos

  • ELEMENTS OF D - BLOCK

    AAKASH SERIES|Exercise EXERCISE - 5.2|33 Videos

Similar Questions

Explore conceptually related problems

The P^(H) of 0.001 M CH_(3) ,COOH is

The molar conductivities of H^(+) and HCOO^(-) ions at infinite dilution are 34.7 and 5.4 mSm^(2) " mol"^(-1) respectively. The molar conductivity of 0.25 M HCOOH is 4.0 mSm^(2) mol^(-1) . Then pK_(a) of formic acid is

The molar conductance at infinite dilution of AgNO_(3), NaCl and NaNO_(3) are 116.5, 110.3 and 105.2 ohm^(-1)cm^(2)"mole"^(-1) respectively. The molar conductance of at infinite dilution is

The equivalent conductivity of 0.1 N CH_3COOH at 25^@ C is 80 and at infinite dilute is 400ohm cm^(2) eq^(-1) . The degree of dissociation of CH_3COOH

The limiting molar conductivities (Lambda^(0)) for NaCl, KBr and KCl are 126, 152 and 150 S. cm^(2) "mol"^(-1) respectively. Then A for NaBr is

At 298 K molar conductivities at infinite dilution ( wedge_(m)^@) of NH_(4)Cl , KOH and KCl are 152.8, 272.6 and 149.8 S cm^(2)mol^(-1) respectively. The wedge_(m)^@ of NH_(4)OH in Scm^(2) mol^(-1) and % dissociation of 0.01 M NH_(4)OH with wedge_(m) =25.1 Scm^(2) mol^(-1) at the same temperature are,