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Calculate the current ( in ma ) required...

Calculate the current ( in ma ) required to deposit 0.195 gr of platinum metal in 5.0 hours from a solution of `PtCl_6^(-2)` ( Atomic weight : pt 195)

A

310

B

31

C

`21.44`

D

`5.36`

Text Solution

Verified by Experts

The correct Answer is:
C
`1F to 1 ` Eq. wt of Pt . `((Pt)/(+4) Cl_6)^(-2) , 96500 C to ((195)/(4))gm`
Q to 0.195 gm , `Q = (0.195 xx 96500)/(((195)/(4))^(1000))=C xx t `
` 96.5 xx 4 = C xx 5 xx 60 xx 60 , C = 0.021145 amp = 21.45 ` milli amp
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