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Let a fully charged lead-storage battery...

Let a fully charged lead-storage battery contains 1.5 L of `5MH_2SO_2`. What will be the concentratis of `H_2SO_4` in the battery after 2.5 ampere current is drawn from the battery for 6 hour?

A

4.626M

B

`0.1865 M `

C

`0.373 M`

D

`9.627 M `

Text Solution

Verified by Experts

The correct Answer is:
A
`1F to 1 ` mole of `H_2SO_4 ` , 96500 CaCl ` to ` 1 mole
` 2.5 xx 6 xx 60 xx 60 to n = ((2.5 xx 6 xx 60 xx 60 xx 1)/(96500)) = 0.5596` moles
` n = (1.5 xx 5-n) =6.9404 , M^(1) = (n^(1))/(V) = (6.9404)/(1.5) = 4.6269M`
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