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In a face centred cubic arrangement of A...

In a face centred cubic arrangement of A and B atoms whose A atoms are at the corner of the unit cell and B atoms at the face centred. One of the A atom is missing from one corner in unit cell. The simplest formula of compound is :

A

`A_(7)B_(3)`

B

`AB_(3)`

C

`A_(7)B_(24)`

D

`A_(7//8)B_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C

A-corners = 8, one atom is missing so `8 - 1 = 7,` Contribution of corner `=7xx(1)/(8)=(7)/(8)`
B-Face centre `= 6`, Contribution `=6xx(1)/(2)=3"   "therefore A(7)/(8)B_(3)"   "A_(7)B_(24)`.
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