A certain oxide of metal M crystallises ...

A certain oxide of metal M crystallises in such a way that `O^(2-)` ions occupy hcp arrangement following AB AB....pattern. The metal ions, however, occupy 2/3rd of the octahedral voids. The formula of the compound is

`M_(2)O_(3)`

`M_(3)O`

`M_(8//3)O_(3)`

`MO_(2)`

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The correct Answer is:

AB-AB-HCP

`O_(-2)` in HCP Array So, `O_(6)`, M occupies `2/3` of OV `=2/3 xx 6 = 12/3, M 12/3 O_(6) rArr M_(12)O_(18) rArr M_(2)_(3)`

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