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The average K.E. of one mole of an ideal...

The average K.E. of one mole of an ideal gas in calories is equal to 

A

3 times of its absolute temp

B

2 times of its absolute temp

C

4 times of its absolute temp

D

2/3 times of its absolute temp

Text Solution

Verified by Experts

The correct Answer is:
A
KE = `3/2 xx RT = 3/2 xx 2T = 3T`
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