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A rarr B, Graph between long(10) P and (...

`A rarr B`, Graph between `long_(10)` P and `(1)/(T)` is a straight line of slope `(1)/(4.606)`. Hence, `Delta H` is

A

1 cal

B

`-4.18` J

C

4 cal

D

`-1` cal

Text Solution

Verified by Experts

The correct Answer is:
B, D
`Delta G^(0) = - RT ln K_(P) = - RT ln P= - 2.303RT log P`
log P `= (-Delta G^(0))/(2.303R).(1)/(T) = (-Delta H^(0))/(2.303RT) + (Delta S^(0))/(2.303R)`
`rArr` slope `= (-Delta H^(0))/(2.303RT) = (1)/(4.606)`
`rArr Delta H^(0) = - 1 "cal" = -4.18J`
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